Progression

1. Arithmetic Progression (AP)

An Arithmetic Progression is a sequence of numbers in which the difference between any two consecutive terms is always the same. This difference is called the common difference (d).

General form:

a, a + d, a + 2d, a + 3d, ...

where

nth term formula:

Tn = a + (n - 1)d

Sum of first n terms:

Sn = n/2 × [2a + (n - 1)d]

Examples:

  1. Find the 10th term of the AP: 3, 7, 11, 15, ...
    Here, a = 3, d = 4.
    Using Tn = a + (n - 1)d,
    T10 = 3 + (10 - 1) × 4 = 3 + 36 = 39.
  2. Find the sum of the first 20 terms of the AP: 5, 8, 11, 14, ...
    Here, a = 5, d = 3, n = 20.
    Using Sn = n/2 × [2a + (n - 1)d],
    S20 = 20/2 × [2 × 5 + (20 - 1) × 3] = 10 × [10 + 57] = 10 × 67 = 670.

2. Geometric Progression (GP)

A Geometric Progression is a sequence where each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio (r).

General form:

a, ar, ar2, ar3, ...

where

nth term formula:

Tn = a × rn-1

Sum of n Terms in a Geometric Progression: Formulas for Different Cases

The formula for the sum of the first n terms depends on the value of the common ratio r:

General Formula (for r ≠ 1)

Sn = a × (rn - 1) / (r - 1)

This formula works for any r ≠ 1, whether r > 1 or r < 1.

Alternative Form (for r < 1)

Sn = a × (1 - rn) / (1 - r)

This is algebraically equivalent and preferred when r < 1 because the numerator stays positive.

Special Case: r = 1

Sn = n × a

If the common ratio is 1, all terms are equal to a, so the sum is just n times a.

Summary Table
Case Formula Notes
r > 1 Sn = a × (rn - 1) / (r - 1) Use as is
0 < r < 1 Sn = a × (1 - rn) / (1 - r) Preferred for positive numerator
r = 1 Sn = n × a All terms equal

Examples:

  1. Find the 6th term of the GP: 2, 6, 18, 54, ...
    Here, a = 2, r = 3.
    Using Tn = a × rn-1,
    T6 = 2 × 35 = 2 × 243 = 486.
  2. Find the sum of the first 5 terms of the GP: 1, 2, 4, 8, 16, ...
    Here, a = 1, r = 2, n = 5.
    Using Sn = a × (1 - rn) / (1 - r),
    S5 = 1 × (1 - 25) / (1 - 2) = (1 - 32) / (1 - 2) = (-31) / (-1) = 31.
  3. Find the sum to infinity of the GP: 5, 2.5, 1.25, 0.625, ...
    Here, a = 5, r = 1/2, and |r| < 1.
    Using S = a / (1 - r),
    S = 5 / (1 - 1/2) = 5 / (1/2) = 10.

Note on Infinite Series

If |r| < 1 and the series is infinite, the sum is:

S = a / (1 - r)

This formula does not apply if |r| ≥ 1.